Optimal. Leaf size=157 \[ -\frac {5 (7 A b-a B)}{8 a^4 b \sqrt {x}}+\frac {A b-a B}{3 a b \sqrt {x} (a+b x)^3}+\frac {7 A b-a B}{12 a^2 b \sqrt {x} (a+b x)^2}+\frac {5 (7 A b-a B)}{24 a^3 b \sqrt {x} (a+b x)}-\frac {5 (7 A b-a B) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{8 a^{9/2} \sqrt {b}} \]
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Rubi [A]
time = 0.04, antiderivative size = 157, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 6, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.207, Rules used = {27, 79, 44, 53,
65, 211} \begin {gather*} -\frac {5 (7 A b-a B) \text {ArcTan}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{8 a^{9/2} \sqrt {b}}-\frac {5 (7 A b-a B)}{8 a^4 b \sqrt {x}}+\frac {5 (7 A b-a B)}{24 a^3 b \sqrt {x} (a+b x)}+\frac {7 A b-a B}{12 a^2 b \sqrt {x} (a+b x)^2}+\frac {A b-a B}{3 a b \sqrt {x} (a+b x)^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 27
Rule 44
Rule 53
Rule 65
Rule 79
Rule 211
Rubi steps
\begin {align*} \int \frac {A+B x}{x^{3/2} \left (a^2+2 a b x+b^2 x^2\right )^2} \, dx &=\int \frac {A+B x}{x^{3/2} (a+b x)^4} \, dx\\ &=\frac {A b-a B}{3 a b \sqrt {x} (a+b x)^3}-\frac {\left (-\frac {7 A b}{2}+\frac {a B}{2}\right ) \int \frac {1}{x^{3/2} (a+b x)^3} \, dx}{3 a b}\\ &=\frac {A b-a B}{3 a b \sqrt {x} (a+b x)^3}+\frac {7 A b-a B}{12 a^2 b \sqrt {x} (a+b x)^2}+\frac {(5 (7 A b-a B)) \int \frac {1}{x^{3/2} (a+b x)^2} \, dx}{24 a^2 b}\\ &=\frac {A b-a B}{3 a b \sqrt {x} (a+b x)^3}+\frac {7 A b-a B}{12 a^2 b \sqrt {x} (a+b x)^2}+\frac {5 (7 A b-a B)}{24 a^3 b \sqrt {x} (a+b x)}+\frac {(5 (7 A b-a B)) \int \frac {1}{x^{3/2} (a+b x)} \, dx}{16 a^3 b}\\ &=-\frac {5 (7 A b-a B)}{8 a^4 b \sqrt {x}}+\frac {A b-a B}{3 a b \sqrt {x} (a+b x)^3}+\frac {7 A b-a B}{12 a^2 b \sqrt {x} (a+b x)^2}+\frac {5 (7 A b-a B)}{24 a^3 b \sqrt {x} (a+b x)}-\frac {(5 (7 A b-a B)) \int \frac {1}{\sqrt {x} (a+b x)} \, dx}{16 a^4}\\ &=-\frac {5 (7 A b-a B)}{8 a^4 b \sqrt {x}}+\frac {A b-a B}{3 a b \sqrt {x} (a+b x)^3}+\frac {7 A b-a B}{12 a^2 b \sqrt {x} (a+b x)^2}+\frac {5 (7 A b-a B)}{24 a^3 b \sqrt {x} (a+b x)}-\frac {(5 (7 A b-a B)) \text {Subst}\left (\int \frac {1}{a+b x^2} \, dx,x,\sqrt {x}\right )}{8 a^4}\\ &=-\frac {5 (7 A b-a B)}{8 a^4 b \sqrt {x}}+\frac {A b-a B}{3 a b \sqrt {x} (a+b x)^3}+\frac {7 A b-a B}{12 a^2 b \sqrt {x} (a+b x)^2}+\frac {5 (7 A b-a B)}{24 a^3 b \sqrt {x} (a+b x)}-\frac {5 (7 A b-a B) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{8 a^{9/2} \sqrt {b}}\\ \end {align*}
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Mathematica [A]
time = 0.18, size = 112, normalized size = 0.71 \begin {gather*} \frac {-105 A b^3 x^3+5 a b^2 x^2 (-56 A+3 B x)+a^3 (-48 A+33 B x)+a^2 b x (-231 A+40 B x)}{24 a^4 \sqrt {x} (a+b x)^3}+\frac {5 (-7 A b+a B) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{8 a^{9/2} \sqrt {b}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.68, size = 105, normalized size = 0.67
method | result | size |
derivativedivides | \(-\frac {2 A}{a^{4} \sqrt {x}}-\frac {2 \left (\frac {\left (\frac {19}{16} A \,b^{3}-\frac {5}{16} B a \,b^{2}\right ) x^{\frac {5}{2}}+\frac {a b \left (17 A b -5 B a \right ) x^{\frac {3}{2}}}{6}+\left (\frac {29}{16} A \,a^{2} b -\frac {11}{16} B \,a^{3}\right ) \sqrt {x}}{\left (b x +a \right )^{3}}+\frac {5 \left (7 A b -B a \right ) \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{16 \sqrt {a b}}\right )}{a^{4}}\) | \(105\) |
default | \(-\frac {2 A}{a^{4} \sqrt {x}}-\frac {2 \left (\frac {\left (\frac {19}{16} A \,b^{3}-\frac {5}{16} B a \,b^{2}\right ) x^{\frac {5}{2}}+\frac {a b \left (17 A b -5 B a \right ) x^{\frac {3}{2}}}{6}+\left (\frac {29}{16} A \,a^{2} b -\frac {11}{16} B \,a^{3}\right ) \sqrt {x}}{\left (b x +a \right )^{3}}+\frac {5 \left (7 A b -B a \right ) \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{16 \sqrt {a b}}\right )}{a^{4}}\) | \(105\) |
risch | \(-\frac {2 A}{a^{4} \sqrt {x}}-\frac {19 x^{\frac {5}{2}} A \,b^{3}}{8 a^{4} \left (b x +a \right )^{3}}+\frac {5 x^{\frac {5}{2}} B \,b^{2}}{8 a^{3} \left (b x +a \right )^{3}}-\frac {17 A \,x^{\frac {3}{2}} b^{2}}{3 a^{3} \left (b x +a \right )^{3}}+\frac {5 B \,x^{\frac {3}{2}} b}{3 a^{2} \left (b x +a \right )^{3}}-\frac {29 \sqrt {x}\, A b}{8 a^{2} \left (b x +a \right )^{3}}+\frac {11 \sqrt {x}\, B}{8 a \left (b x +a \right )^{3}}-\frac {35 \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) A b}{8 a^{4} \sqrt {a b}}+\frac {5 \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right ) B}{8 a^{3} \sqrt {a b}}\) | \(163\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.49, size = 132, normalized size = 0.84 \begin {gather*} -\frac {48 \, A a^{3} - 15 \, {\left (B a b^{2} - 7 \, A b^{3}\right )} x^{3} - 40 \, {\left (B a^{2} b - 7 \, A a b^{2}\right )} x^{2} - 33 \, {\left (B a^{3} - 7 \, A a^{2} b\right )} x}{24 \, {\left (a^{4} b^{3} x^{\frac {7}{2}} + 3 \, a^{5} b^{2} x^{\frac {5}{2}} + 3 \, a^{6} b x^{\frac {3}{2}} + a^{7} \sqrt {x}\right )}} + \frac {5 \, {\left (B a - 7 \, A b\right )} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{8 \, \sqrt {a b} a^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 2.98, size = 445, normalized size = 2.83 \begin {gather*} \left [\frac {15 \, {\left ({\left (B a b^{3} - 7 \, A b^{4}\right )} x^{4} + 3 \, {\left (B a^{2} b^{2} - 7 \, A a b^{3}\right )} x^{3} + 3 \, {\left (B a^{3} b - 7 \, A a^{2} b^{2}\right )} x^{2} + {\left (B a^{4} - 7 \, A a^{3} b\right )} x\right )} \sqrt {-a b} \log \left (\frac {b x - a + 2 \, \sqrt {-a b} \sqrt {x}}{b x + a}\right ) - 2 \, {\left (48 \, A a^{4} b - 15 \, {\left (B a^{2} b^{3} - 7 \, A a b^{4}\right )} x^{3} - 40 \, {\left (B a^{3} b^{2} - 7 \, A a^{2} b^{3}\right )} x^{2} - 33 \, {\left (B a^{4} b - 7 \, A a^{3} b^{2}\right )} x\right )} \sqrt {x}}{48 \, {\left (a^{5} b^{4} x^{4} + 3 \, a^{6} b^{3} x^{3} + 3 \, a^{7} b^{2} x^{2} + a^{8} b x\right )}}, -\frac {15 \, {\left ({\left (B a b^{3} - 7 \, A b^{4}\right )} x^{4} + 3 \, {\left (B a^{2} b^{2} - 7 \, A a b^{3}\right )} x^{3} + 3 \, {\left (B a^{3} b - 7 \, A a^{2} b^{2}\right )} x^{2} + {\left (B a^{4} - 7 \, A a^{3} b\right )} x\right )} \sqrt {a b} \arctan \left (\frac {\sqrt {a b}}{b \sqrt {x}}\right ) + {\left (48 \, A a^{4} b - 15 \, {\left (B a^{2} b^{3} - 7 \, A a b^{4}\right )} x^{3} - 40 \, {\left (B a^{3} b^{2} - 7 \, A a^{2} b^{3}\right )} x^{2} - 33 \, {\left (B a^{4} b - 7 \, A a^{3} b^{2}\right )} x\right )} \sqrt {x}}{24 \, {\left (a^{5} b^{4} x^{4} + 3 \, a^{6} b^{3} x^{3} + 3 \, a^{7} b^{2} x^{2} + a^{8} b x\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 2660 vs.
\(2 (146) = 292\).
time = 93.63, size = 2660, normalized size = 16.94 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.79, size = 110, normalized size = 0.70 \begin {gather*} \frac {5 \, {\left (B a - 7 \, A b\right )} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{8 \, \sqrt {a b} a^{4}} - \frac {2 \, A}{a^{4} \sqrt {x}} + \frac {15 \, B a b^{2} x^{\frac {5}{2}} - 57 \, A b^{3} x^{\frac {5}{2}} + 40 \, B a^{2} b x^{\frac {3}{2}} - 136 \, A a b^{2} x^{\frac {3}{2}} + 33 \, B a^{3} \sqrt {x} - 87 \, A a^{2} b \sqrt {x}}{24 \, {\left (b x + a\right )}^{3} a^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.28, size = 147, normalized size = 0.94 \begin {gather*} -\frac {\frac {2\,A}{a}+\frac {11\,x\,\left (7\,A\,b-B\,a\right )}{8\,a^2}+\frac {5\,b^2\,x^3\,\left (7\,A\,b-B\,a\right )}{8\,a^4}+\frac {5\,b\,x^2\,\left (7\,A\,b-B\,a\right )}{3\,a^3}}{a^3\,\sqrt {x}+b^3\,x^{7/2}+3\,a^2\,b\,x^{3/2}+3\,a\,b^2\,x^{5/2}}-\frac {5\,\mathrm {atan}\left (\frac {5\,\sqrt {b}\,\sqrt {x}\,\left (7\,A\,b-B\,a\right )}{\sqrt {a}\,\left (35\,A\,b-5\,B\,a\right )}\right )\,\left (7\,A\,b-B\,a\right )}{8\,a^{9/2}\,\sqrt {b}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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